Denise earns $30 an hour. She wants to purchase a computer that costs $2000. Create and solve an inequality to determine the least amount of hours she must work in order to be able to purchase the computer.

Answer:

$30h\geq 2000\ or\\h\geq67$

Denise has to work at least 67 hours in order to buy a computer that costs $2000.

Step-by-step explanation:

Given:

Hourly earning of Denise is $30.

Let the number of hours Denise works be 'h'.

Now, total earning of Denise can be calculated using the unitary method and is given as:

$Total\ money=\textrm{Hourly earning}\times \textrm{Total hours worked}\\Total\ money=30\times h\\Total\ money=30h$

Now, total money earned by Denise must be at least $2000 in order to purchase a computer. Therefore, the inequality is given as:

$30h\geq 2000\\h\geq \frac{2000}{30}\\h\geq 66.7$

Therefore, Denise has to work at least 67 hours in order to buy a computer that costs $2000.

7 0

3 years ago

jasmine pet guinea pig gained8 ounces in one month.Write an integer to describe the amount of weight her pet gained

bonufazy [111]

It would just be 8 since an integer just means whole number.

3 0

3 years ago

A researcher believes that 5% of pet dogs in Europe are Labradors. If the researcher is right, what is the probability that the

DerKrebs [107]

Answer:

0.9036

Step-by-step explanation:

Calculation to determine the probability that the proportion of Labradors

P(Proportion greater than 4%)

= P(z> 0.04 -0.05 /√0.05 * 0.95/806

= P(z > -1.30)

=0.9036

Thereforethe probability that the proportion of Labradors is =0.9036

6 0

3 years ago