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2 years ago

5

A floor 3.2m long and 2.8 m wide is to be covered with square shaped tiles of length 10cm. Find the coast of flooring if the coa

st tiles is Rs 150 per 100 tile.

1 answer:

Aloiza [94]2 years ago

6 0

Answer:

1344

Step-by-step explanation:

100cm = 1 m

Convert the dimensions of the floor to cm = Area of a rectangle = length x breadth = 320 x 280 = 89,600m²

Area of a square = length² = 10cm² = 100cm²

Number of tiles that would be needed = area of floor / area of square

89,600cm² / 100cm² = 896

Cost of one tile = rs 150 / 100 = 1.5

Cost of 896 tiles = 1.5 x 896 = 1344

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mafiozo [28]

(x, y)

The domain are all the x-values, the range are all the y-values.

R={(19,96),(20,101),(21,106),(22,111)}

The domain is: 19, 20, 21, and 22
The range is: 96, 101, 106, and 111

7 0

3 years ago

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Solve by addition method <br>3x+y=8 <br>2x-y=7

Vinil7 [7]

Answer:

(3,-1)

Step-by-step explanation:

So we have the system of equations:

$3x+y=8\\2x-y=7$

As directed, add straight down. The y-variable will cancel:

$5x=15$

Now, divide both sides by 5. The left cancels:

$x=3$

So x is 3.

Now, substitute 3 for x in either of the equations:

$3x+y=8$

Substitute 3 for x:

$3(3)+y=8$

Multiply:

$9+y=8$

Subtract 9 from both sides:

$y=-1$

So, our answer is: x=3, y=-1 or (3,-1).

And we are done :)

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3 years ago

If f(1) = 10 and f(n) = f(n = 1) – 4 then find the value of f(5).

svetoff [14.1K]

Given:

$f(1)=10$ and $f(n)=f(n-1)-4$ .

To find:

The value of f(5).

Solution:

We have,

$f(n)=f(n-1)-4$

For $n=2$ ,

$f(2)=f(2-1)-4$

$f(2)=f(1)-4$

$f(2)=10-4$

$f(2)=6$

For $n=3$ ,

$f(3)=f(3-1)-4$

$f(3)=f(2)-4$

$f(3)=6-4$

$f(3)=2$

For $n=4$ ,

$f(4)=f(4-1)-4$

$f(4)=f(3)-4$

$f(4)=2-4$

$f(4)=-2$

For $n=5$ ,

$f(5)=f(5-1)-4$

$f(5)=f(4)-4$

$f(5)=-2-4$

$f(5)=-6$

Therefore, the value of $f(5)$ is $-6$ .

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3 years ago

pleeeeeeeeeeeease hellllllllp meeeeeee the circle has a center of 0.its raduis is 3 cm,and the central angle A measures 100.what

Vsevolod [243]

Answer:

2.5 pi

Step-by-step explanation:

Comment

If you were trying to get the area of a whole circle, you would use

Area = pi r^2

You have to modify the formula to show that just part of the circle has an area that you are interested in.

The new formula is

Area = (theta/360) pi r^2

Givens

r = 30 cm

theta = 100

Solution

Area = (100 / 360) * pi * r^2 Substitute the givens into this formula

Area = (5 / 18) * pi * 3^2 Expand

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Area = 5/2 * pi

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2 years ago

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ss7ja [257]

Answer: Carolynn is faster.

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3 years ago