Mark all of the statements that are true.

Evaluate the following multiplication expression: -2(11)

matrenka [14]

Answer:

the answer is negative 22

Step-by-step explanation:

-2 x 11 = -22

4 0

3 years ago

Please help me answer this will give brainlst

VladimirAG [237]

Answer:

17° and 73°

Step-by-step explanation:

For two complementary angles, the sum of angles is equal to 90 degrees.

Let other angles = x

First angle = 5+4x ...(1)

ATQ,

5+4x+x=90 ...(2)

Equation (1) and (2) shows the equations for the given problems.

5+5x=90

5x = 85

x = 17°

Other angle = 17

First angle = 5+4x

= 5+4(17)

= 73°

So, the other two angles are 17° and 73° respectively.

8 0

3 years ago

The volume of a cylinder, V, in terms of radius, r,

Igoryamba

Answer:

See explanation

Step-by-step explanation:

Volume of a cylinder = πr²h

Solve for r

V = π * r² * h

r² = V/πh

Find the square root of both sides

r = √V/πh

If height = 6 meters and volume = 300 cubic meters. Find r

r = √V/πh

= √(300/3.14*6)

= √(300/18.84)

= √15.923566878980

r = 3.9904344223381

Approximately,

r = 4 meters

5 0

3 years ago

Suppose that a box contains r red balls and w white balls. Suppose also that balls are drawn from the box one at a time, at rand

dybincka [34]

Answer: Part a) $P(a)=\frac{1}{\binom{r+w}{r}}$

part b) $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}$

Step-by-step explanation:

The probability is calculated as follows:

We have proability of any event E = $P(E)=\frac{Favourablecases}{TotalCases}$

For part a)

Probability that a red ball is drawn in first attempt = $P(E_{1})=\frac{r}{r+w}$

Probability that a red ball is drawn in second attempt= $P(E_{2})=\frac{r-1}{r+w-1}$

Probability that a red ball is drawn in third attempt = $P(E_{3})=\frac{r-2}{r+w-1}$

Generalising this result

Probability that a red ball is drawn in [tex}i^{th}[/tex] attempt = $P(E_{i})=\frac{r-i}{r+w-i}$

Thus the probability that events $E_{1},E_{2}....E_{i}$ occur in succession is

$P(E)=P(E_{1})\times P(E_{2})\times P(E_{3})\times ...$

Thus $P(E)$ = $\frac{r}{r+w}\times \frac{r-1}{r+w-1}\times \frac{r-2}{r+w-2}\times ...\times \frac{1}{w}\\\\P(E)=\frac{r!}{(r+w)!}\times (w-1)!$

Thus our probability becomes

$P(E)=\frac{1}{\binom{r+w}{r}}$

Part b)

The event " r red balls are drawn before 2 whites are drawn" can happen in 2 ways

1) 'r' red balls are drawn before 2 white balls are drawn with probability same as calculated for part a.

2) exactly 1 white ball is drawn in between 'r' draws then a red ball again at $(r+1)^{th}$ draw

We have to calculate probability of part 2 as we have already calculated probability of part 1.

For part 2 we have to figure out how many ways are there to draw a white ball among (r) red balls which is obtained by permutations of 1 white ball among (r) red balls which equals $\binom{r}{r-1}$

Thus the probability becomes $P(E_i)=\frac{\binom{r}{r-1}}{\binom{r+w}{r}}=\frac{r}{\binom{r+w}{r}}$

Thus required probability of case b becomes $P(E)+ P(E_{i})$

= $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}\\\\$

7 0

4 years ago

The enrollment in college A may be modeled by y = 0.046x + 0.570, and the enrollment in college B may be modeled by y = –0.036x

zhuklara [117]

You want to know when both colleges have the same enrollment. "When" is a time thing so you are going to be solving for x. The number of students is the same and that means you will be solving for y.

Since both ys are equal, you can equate the right side of each equation to each other.

0.046 x + 0.570 = - 0.036x + 2.702 There are a number of ways to go on. The easiest is to dig out your calculator. Add 0.036x to both sides.
0.046x + 0.036x + 0.570 = 2.702
0.082x + 0.570 = 2.702 Now subtract 0.570 from both sides.
0.082x = 2.702 - 0.570
0.082x = 2.132 Divide by 0.084
x = 2.132 / 0.082
x = 26 which means you add 26 onto 1990. The year this took place was 2016
x = 2016 (That's the year there was equality in enrollment). The second one is the only year that gives 2016 as an answer. So you don't have to find y. But we'll do it anyway.

Now you have to solve for y
y = 0.046x +0.57 put 26 in for x
y = 0.046 * 26 + 0.570
y = 1.196 + 0.570
y = 1.766 enrollment numbers were equal, but this is in thousands.
y = 1766 enrollment in actual numbers of students.

Second choice <<<<<===== answer.

8 0

3 years ago