Answer:
<h2>
63° or 173°</h2>
Step-by-step explanation:
You didn't specify where the point P is so there are two posibilites:
1.
P₁Z is dividing angle OZQ
then:
m∠P₁ZQ = m∠OZQ - m∠OZP₁ = 125° - 62° = 63°
2.
P₂Z is outside angle OZQ
then
m∠P₂ZQ = 360° - (m∠OZQ + m∠OZP₂) = 360° - (125° + 62°) = 173°
Answer:
46.6 ft/sec (to the nearest tenth)
Step-by-step explanation:
There's a common identity useful here: 60 mph = 88 ft/sec.
Mult. 31.8 mph by the conversion factor (88 ft/sec) / (60 mph), obtaining:
46.64 ft/sec.
Answer:
The answer is A I believe.
The formula is y2 - y1/x2 - x1. The answer would be 3/4 once simplified.
Answer:
I think so, yes.
Step-by-step explanation:
Let's insert a few cases that might help clear up this issue:
Let's say you have a width of 0.5, and a length of 2.
The area is still 1.
Also, if we have a case, where length is 0.25, and the width is 4,
The area is still 1.
I think that proves the point that the LENGTH can be greater than 1 yard.
