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Stells [14]
3 years ago
15

Simplify each expression, and then arrange them in increasing order based on the coefficient of n2. -5(n3 – n2 – 1) + n(n2 – n)

(n2 – 1)(n + 2) – n2(n – 3) n2(n – 4) + 5n3 – 6 2n(n2 – 2n – 1) + 3n2

Mathematics
1 answer:
valkas [14]3 years ago
8 0

Answer:

Step-by-step explanation:

-5(n^3 - n^2 - 1) + n(n^2 - n)

-5n^3 + 5n^2 + 5 + n^3 - n^2

-4n^3 + 4n^2 + 5 <===

(n^2 - 1)(n + 2) - n^2(n - 3)

n^2(n + 2) - 1(n + 2) - n^3 + 3n^2

n^3 + 2n^2 - n - 2 - n^3 + 3n^2

5n^2 - n - 2 <===

n^2(n - 4) + 5n3 - 6

n^3 - 4n^2 + 5n^3 - 6

6n^3 - 4n^2 - 6 <===

2n(n^2 - 2n - 1) + 3n^2

2n^3 - 4n^2 - 2n + 3n^2

2n^3 -n^2 - 2n <===

putting them in order based on the coefficient n^2 is :

6n^3 - 4n^2 - 6

2n^3 - n^2 - 2n

-4n^3 + 4n^2 + 5

5n^2 - n - 2

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