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Georgia [21]
3 years ago
10

3-5 = 4a - 7(1 - 5a)

Mathematics
1 answer:
Semmy [17]3 years ago
5 0

Answer:

  a = 5/39

Step-by-step explanation:

We assume you want to solve the equation for "a".

  -2 = 4a -7 +35a . . . . simplify

  5 = 39a . . . . . . . . . .  add 7

  5/39 = a . . . . . . . . . divide by the coefficient of a

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Order these numbers in ascending order. -11/3, 90%, 89/4, 2​
Delicious77 [7]

Answer:

-  \frac{11}{3} \:   \: »  \: \: 90\% \: »  \: \: 2 \: \:  » \: \:   \frac{89}{4}

5 0
2 years ago
If AB = 9, RS = 3, and SC = 5, find BC.<br> A) 5<br> B) 10<br> C) 13.5<br> D) 15
Ronch [10]

Answer:

D

Step-by-step explanation:

Δ ABC and Δ RSC are similar triangles, thus the ratio of corresponding sides are equal, that is

\frac{BC}{SC} = \frac{AB}{RS}, substitute values

\frac{BC}{5} = \frac{9}{3} = 3 ( multiply both sides by 5 )

BC = 5 × 3 = 15 → D

8 0
3 years ago
Read 2 more answers
Suppose that a large pumpkin empty a swimming pool in 40 hours and that a small pumpkin empty a pool and 70 hours working togeth
Norma-Jean [14]

Answer:

Total 25.45 hours will be taken to empty the pool.

Step-by-step explanation:

Time taken by large pumpkin to empty the pool=40 hours

Time taken by the smaller pumpkins to empty the pool=70 hours

Amount of pool emptied by large pumpkin in one hour=\frac{1}{40}

Amount of pool emptied by small pumpkin in one hour=\frac{1}{70}

Amount of pool emptied in one hour if both pumpkins work together=

\frac{1}{40}+ \frac{1}{70}

=\frac{11}{280}

Therefore, the no. of days will be the reciprocal of the amount of work done in one hour ie . \frac{280}{11}

Total 25.45 hours will be taken to empty the pool.

5 0
3 years ago
Prove why this makes sense.
olchik [2.2K]

Answer:

it doesn't

Step-by-step explanation:

hehe, try again

6 0
2 years ago
Read 2 more answers
Three years ago, Andy invested $7,000 in an account that earns 10% interest compounded annually.
Serggg [28]
Andy has $9317.00, to find your answer, do y=7000(1.10)^3 and you get 9317.
7 0
3 years ago
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