Answer:
6.83 units
Step-by-step explanation:
Let the height of the original pyramid be represented by h. Then the cut off top has a height of (h -2). The scale factor for the area is the square of the scale factor for height, so we have ...
(height ratio)^2 = 1/2
((h -2)/h)^2 = 1/2
(h -2)√2 = h . . . . . . square root; multiply by h√2
h(√2 -1) = 2√2 . . . . add 2√2 -h
h = (2√2)/(√2 -1) ≈ 6.8284 . . . units
The altitude of the original pyramid is about 6.83 units.
I feel like there is something missing from this question, for example how large is the tree house? If these are just plain measurements, then I would opt for B.
Arc Length = radius * Angle in radians
Arc Length = 27.4 *
<span>
<span>
<span>
5.4977871438
</span>
</span>
</span>
Arc Length =
<span>
<span>
<span>
150.6393677396
</span>
</span>
</span>
inches
Source:
http://www.1728.org/radians.htm
Answer:
The correct option is 4.
Step-by-step explanation:
The given expression is
Simplify the given expression.
![[\because x^mx^n=x^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20x%5Emx%5En%3Dx%5E%7Bm%2Bn%7D%5D)
Therefore correct option is 4.
Answer:
15+2a
Step-by-step explanation:
7+a+8+a=15+2a
