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Ierofanga [76]
3 years ago
11

If f(x) =2x3 - 1, then f(-3)=

Mathematics
2 answers:
Vadim26 [7]3 years ago
4 0

Answer:

f(-3)=-19

Step-by-step explanation:

-3 REPLACES THE x

MA_775_DIABLO [31]3 years ago
3 0

Answer:

Step-by-step explanation:

f(x) = 2x^3 - 1

if x = -3,

f(-3) = 2 × (-3)^3 - 1

= 2 × -27 - 1

= -54 -1

= -55

hope this helps

plz mark it as brainliest!!!!!!!!!

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Yvette is starting a jewelry business. She spends $120 on supplies and makes 18 necklaces. She wants to earn a profit equal to 3
kiruha [24]

Yvette wants to earn a profit of $360, then. That means she has to make a total of $480. 480 divided by 18 is 26 and 2/3. That basically rounds up to $26.67.


480 = 18x


360 = 18x - 120


120(3) = 18x - 120


(I'm not that good at this, so don't take my word for it)

4 0
3 years ago
Find the exact value of cos(arcsin(1/4)). For full credit, explain your reasoning.
Westkost [7]
First way
arcsin(1/4) means that 1/4 sin of the angle.

sin(α)=1/4
sin²α+cos²α=1
(1/4)²+cos²α=1
cos²α=1-1/16 =15/16
cosα=+/-(√15)/4

<span>Second way
</span>
sin(α)=1/4 =opposite leg/hipotenuse
cos(α)=adjacent leg/hypothenuse
adjacent leg =√(hypotenuse²- Opposite²)=√(16-1)=√15
cosα=+/-√15/4

For one value of sinα, possible 2 values of cosα.

5 0
2 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
2 years ago
(Fill in the blank)<br> Solve the following equation.
swat32

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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