X= r-h/y
h= xy-r/-1
r= xy+h
Answer:
777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777
Step-by-step explanation:
Answer:
Sorry this is late and I think this is right.
They are both parallel, they have the same slope, and do <em>not </em>intersect. If you were to draw a slope out for it, you would find this to be true.
For example: Say the question called for you to explain why there aren't any solutions to these system of inequalities:
<em>y < - 1/2x -3</em>
<em>y > 1/2x + 2</em>
<em>y= -x/2 -3</em> and <em>y= -x/2 + 2 </em>have the same exact slope, are parallel, and never intersect. The first line is 5 units below the second line when x = 0. Because the lines are parallel, it is always below the second line. The solutions of y < - x/2 -3 are the points in the plane below the first line. The solutions of y > 1/2 + 2 are points above the second line.
I hope this helps you. Good luck on whatever you're working on and stay safe! Please let me know if this helped you or didn't.
Answer:
<em>64 degrees</em>
Step-by-step explanation:
When you have the SRQ angle, you can easily solve for PQR. Luckily, we're given that QRP and PRS are 32 and 84, respectively. Adding this together gives you 116. 116*2 = 232 and 360-232 = 128, and 128/2 = 64.
<em>Please Mark Brainliest if this helps!</em>
