Answer:
The answer is A I hope this helps, if not I apologize.
Explanation:
maintenance is the answer
Answer:
The correct selection is the letter C. The first ACL is denying all TCP traffic and the other ACLs are being ignored by the router.
Explanation:
In this case, the letter C is the right answer because with the first ACL exactly:
access-list 102 deny tcp any any
We are denying all traffic with the next line deny tcp any any, in this case, the others line are being ignored.
access-list 104 permit udp host 10.0.0.3 any
access-list 110 permit tcp host 10.0.0.2 eq www any
access-list 108 permit tcp any eq ftp any
For that nobody can access to the internet, the security administrator of ABC must change the first ACL.
Answer:
int k;
double d;
char s[10];
cin >> k >> d >> s;
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s;
Explanation
First Step (declare K, d, s) so they can store a integer
int k;
double d;
char s[10];
Second Step (read in an integer, a real number and a small word)
cin >> k >> d >> s;
Third Step ( print them out )
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s;
Answer:
public static String repeat(String text, int repeatCount) {
if(repeatCount < 0) {
throw new IllegalArgumentException("repeat count should be either 0 or a positive value");
}
if(repeatCount == 0) {
return "";
} else {
return text + repeat(text, repeatCount-1);
}
}
Explanation:
Here repeatCount is an int value.
at first we will check if repeatCount is non negative number and if it is code will throw exception.
If the value is 0 then we will return ""
If the value is >0 then recursive function is called again untill the repeatCount value is 0.
