Answer:
domain: {-12, -8, 0, 1} range: {0, 8, 12}
Step-by-step explanation:
domain are of all the input values shown on the x-axis. The range is the set of possible output shown on the y-axis.
Answer:
B. 0.268
Step-by-step explanation:
if there are more than half boys then girls it as t be und .5 since that's half and .018 is to low
Answer:
Solution:
the boat's speed in still water: x
The speed with current: (x+3)
The speed against current: (x-3)
The equation is
3(x+3) = 4(x-3)
x = 21 mph
The distance = 3*(21+3)= 72 miles
I choose (A)
Step-by-step explanation:
Answer:
Check below, please.
Step-by-step explanation:
Hi, there!
Since we can describe eccentricity as 
a) Eccentricity close to 0
An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

b) Eccentricity =5

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

c) Eccentricity close to 1
In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.


Answer: 15/91 which is choice B
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There are two methods to find this answer.
Method 1) We have 6 girls and 8+6 = 14 students. The probability of picking a girl is 6/14 = 3/7. After the first girl is chosen, we have 5 girls left out of 14-1 = 13 students overall. The probability of picking another girl (assuming the first selection was a girl) is 5/13. Multiply these probabilities: (3/7)*(5/13) = (3*5)/(7*13) = 15/91
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Method 2) We can use the nCr combination formula. Order does not matter.
We have nCr = 6 C 2 = 15 ways to pick 2 girls. See the attached image below for the steps (figure 1)
Out of nCr = 14 C 2 = 91 ways to pick 2 students. See the attached image below for the steps (figure 2)
So that's another way to get the answer 15/91.