3 years ago

Determine if the relation represents a function. Explain

Mathematics

1 answer:

Taya2010 [7]3 years ago

5 0

It's a function because each input has one output

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Written equation for y=-2=1 (0,3)

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Is that supposed to be y=-2x+1?
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3 years ago

PLEASE HELP!!!!!!!!!

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Step-by-step explanation:

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3 years ago

Mrs Thomas played a game. Her score changed the same amount each round. After 3 rounds, her score had changed by -18 points. How

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3 years ago

Please I need help with this!!!!!!!

inysia [295]

Answer:

Step-by-step explanation:

1). Step 4:

$x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}$

$x=\sqrt[3]{5^4}$ [Since, $a^{\frac{1}{3}}=\sqrt[3]{a}$ ]

$x=\sqrt[3]{5\times 5\times 5\times 5}$

Step 5:

$x=\sqrt[3]{(5)^3\times 5}$

$x=\sqrt[3]{5^3}\times \sqrt[3]{5}$

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

$(3x-1)^{\frac{1}{5}}=2$

Step 1:

$(3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}$

Step 2:

$(3x-1)=2^5$

Step 3:

$3x=32+1$

Step 4:

$x=11$

4). By substituting $x=11$ in the original equation.

$(3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}$

$=(2^5)^\frac{1}{5}$

$=2$

There is no extraneous solution.

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3 years ago