4 years ago

Can you please solve this question with procedure, please???? . h (x) = 6x^2+ 3x + 1

Mathematics

1 answer:

algol134 years ago

7 0

Answer:

Step-by-step explanation:

$6x^2+3x+1=0\\a=6,b=3,c=1\\(-b+-\sqrt{b^2-4ac} )/2a\\\\\frac{-3+-\sqrt{-15} }{12} \\\\$

The roots are:

$\frac{-3+-i\sqrt{15} }{12}$

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