Answer:
e)The information from the sample does not give enough information to support that more than 70% of Canadian children receive antibiotics during the first year of life
Step-by-step explanation:
The proportion we will use for the test is p = 70 %
From a random sample we got
n = 616
x = 438 then p₁ = 438/616 p₁ = 0,71 p₁ = 71 %
Then q₁ = 1 - p₁ q₁ = 1 - 0,71 q₁ = 0,29 q₁ = 29 %
a) Hypothesis test:
Null hypothesis H₀ p₁ = p
Alternative hypothesis Hₐ p₁ > p >70 %
CI = 95 % significance level α = 5 % α = 0,05
z(c) for α = 0,05 from z-table is z(c) = 1,64
b) To calculate z(s) = ( p₁ - p ) / √ p₁*q₁ / n
z(s) = ( 0,71 - 0,70 )/ √ 0,71*0,29/616
z(s) = 0,01 /0,01828
z(s) = 0,547 ≈ 0,55
c) p-value for z(s) is from z-table p-value ≈ 0,7088
d) p-value > 0,05 then we accept H₀ we don´t have enough evidence to reject H₀
e)The information from the sample does not give enough information to support that more than 70% of Canadian children receive antibiotics during the first year of life
where c is the </span><span>hypotenuse and a and b are the other two sides. To solve for one of the shorter sides we need to rearrange:
