The given polynomial expressed as partial fraction is 5x^3 + 9/x
<h3>Polynomial function and partial fractions</h3>
Polynomial function are function that have a leading degree of 3. Given the expression below;
f(x) = (5x^4+9)/x
Applying partial fraction
Since the part fraction means separating the fraction into two parts, hence;
f(x) = 5x^4/x + 9/x
Simplify
Since there is value of x at both numerator and denominator, it will cancel out to have
f(x) = 5x^3 + 9/x
From the result, we can see that p(x) = 5x^3 and k = 9
Hence the given polynomial expressed as partial fraction is 5x^3 + 9/x
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If BC is parallel to DE then ∠D ≅ ∠B and ∠E ≅ ∠C. Therefore
ΔABC is similar to ΔADE.
The sides of smaller triangle are in proportion with sides of bigger triangle.
Therefore we have the equation:
We have AC = x, AE = x + 15, AB = 8, AD = 8 + 10 = 18.
Substitute:
<em>cross multiply</em>
<em>use distributive property a(b + c) = ab + ac</em>
<em>subtract 8x from both sides</em>
<em>divide both sides by 10</em>
<h2>Answer: AC = 12</h2>
Four hundred thrity-three point thirty eight
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Answer:
x = sqroot(122)
Step-by-step explanation:
First find the line that goes thru the middle of the shape. It is the hypotenuse of the bottom/left triangle. Use the pythagorean thm.
9^2 + 5^2 = h^2
81 + 25 = h^2
sqroot106 = h
Now sqroot106 is a leg in the right triangle that is on the top/right in the image.
Use pythagorean thm again.
4^2 + (sqroot106)^2
= x^2
16 + 106 = x^2
122 = x^2
sqroot122 = x
