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Artist 52 [7]
3 years ago
6

What is the value of p? A) 55 B) 45 C) 35 D) 125

Mathematics
1 answer:
Margarita [4]3 years ago
7 0

Answer:

35

Step-by-step explanation:

just subtract 125 and 99

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What adds to 12 and multiplies to 8
Ipatiy [6.2K]
X+y= -12 xy=8 y=8/x x+8/x=-12 x^2+12x+8=0 This has no integral
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How many times greater is 1 1/2 then 1/4
Vlad [161]
6 times

6 * 1/4 is 6/4
6/4 is 1 2/4 which is 1 1/2
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3 years ago
4. If a data set is graphed, what type of graph would form if the data shows a direct variation?
Lady bird [3.3K]

A function represents a direct variation if the ratio between the output values and input values is constant. If two quantities vary directly, the points on a graph form a straight line, and the line runs through the origin.

Please leave a Thanks! It helps!

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=if%20%5C%3A%20%28%20%5Cfrac%7B3%7D%7B4%7D%20%29%5E%7B6%7D%20%20%5Ctimes%20%28%20%5Cfrac%7B16%7
zhenek [66]

Answer:

2

Step-by-step explanation:

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{x+2}

\frac{3^6}{4^6} \cdot \frac{16^5}{9^5}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{4^6} \cdot \frac{(4^2)^5}{(3^2)^5}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{4^6} \cdot \frac{4^{10}}{3^{10}}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{3^{10}} \cdot \frac{4^{10}}{4^6}=\frac{4^{x+2}}{3^{x+2}}

3^{-4} \cdot 4^{4}=4^{x+2}3^{-(x+2)}

This implies

x+2=4

and

-(x+2)=-4.

x+2=4 implies x=2 since subtract 2 on both sides gives us x=2.

Solving -(x+2)=-4 should give us the same value.

Multiply both sides by -1:

x+2=4

It is the same equation as the other.

You will get x=2 either way.

Let's check:

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{2+2}

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{4}

Put both sides into your calculator and see if you get the same thing on both sides:

Left hand side gives 256/81.

Right hand side gives 256/81.

Both side are indeed the same for x=2.

4 0
3 years ago
Find the determinant of the matrix.
Natalka [10]

Answer:

0

Step-by-step explanation:

\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc

0(4)-4(0) = 0

8 0
3 years ago
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