Given the data from the question, reaction 2 is 2.83 times faster compared to reaction 1
<h3>Data obtained from the question</h3>
- Molarity of reaction 1 (R₁) = 0.180 mol/L
- Molarity of reaction 2 (R₂) = 0.510 mol/L
- Comparison =?
<h3>How to determine the comparison of reaction 2 to reaction 1</h3>
We can determine how many times faster is reaction 2 to reaction by doing the following:
R₂ / R₁ = 0.510 / 0.180
R₂ / R₁ = 2.83
Cross multiply
R₂ = 2.83 × R₁
From the above illustration, we can see that reaction 2 is 2.83 times faster than reaction 1
Learn more about Graham's law of diffusion:
brainly.com/question/14004529
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Formula:
(3.14)r^2
Larger one:
(3.14)(3)^2
28.26 * 13
367.38 in^2
Smaller one:
(3.14)(3)^2
28.26 * 8
226.08 in^2
With wat?
Yes
Step by step explanation
Answer:
Step-by-step explanation:
3/4+12/8+3/2+10/8=5
Answer:
x = -11
Step-by-step explanation:
First, add three to both sides on the equation. Then, your equation becomes 55= -5x. Finally, divide both sides by -5 to get -11 = x. So, x equals -11. Hope this helps!
