I need help please?!!!):

Can you answer number 3, 4, and 5?<br> (Whoever is right gets brainliest)

valkas [14]

Answer:

3: 200, 200

4:800

5:400

Step-by-step explanation:

:)

3 0

3 years ago

Read 2 more answers

Tara wants to fix the location of a mountain by taking measurements from two positions 3 miles apart. From the first position, t

Black_prince [1.1K]

Answer:

Shortest distance from the mountain is 3.17 miles.

Step-by-step explanation:

From the figure attached,

Let a mountain is located at point A.

Angle between the mountain and point B (∠B) = 53°

Angle between the mountain and point C (∠C) = 78°

Distance between these points = 3 miles

Since, m∠A + m∠B + m∠C = 180°

m∠A + 53° + 78° = 180°

m∠A = 180°- 131° = 49°

By applying sine rule in triangle ABC,

$\frac{\text{sin}(49)}{BC}=\frac{\text{sin}(53)}{AC}= \frac{\text{sin}(78)}{AB}$

$\frac{\text{sin}(49)}{3}=\frac{\text{sin}(53)}{AC}= \frac{\text{sin}(78)}{AB}$

$\frac{\text{sin}(49)}{3}=\frac{\text{sin}(53)}{AC}$

AC = $\frac{3\text{sin}(53)}{\text{sin}(49)}$

AC = 3.17 miles

$\frac{\text{sin}(49)}{3}=\frac{\text{sin}(78)}{AB}$

AB = $\frac{3\text{sin}(78)}{\text{sin}(49)}$

AB = 3.89 miles

Therefore, shortest distance from the mountain is 3.17 miles.

7 0

3 years ago

In which quadrant is the number –14 – 5i located on the complex plane?

loris [4]

Answer:

The complex number $r = -14 - i\,5$ belongs to the third quadrant of the complex plane.

Step-by-step explanation:

Let be $r = -14 - i\,5$ . In the complex plane, if $\Re (r) < 0$ (real component) and $\Im (r) < 0$ (imaginary component), the number belongs to the third quadrant of the complex plane. The complex number $r = -14 - i\,5$ belongs to the third quadrant of the complex plane.