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Dimas [21]
3 years ago
11

I don’t know how to solve for Q.

Mathematics
1 answer:
Naya [18.7K]3 years ago
8 0

Answer:

  ∠Q = 75°

Step-by-step explanation:

Start by recognizing that the triangle is isosceles (the long sides are marked as being equal-length). That means angles Q and R have the same measure.

Next, you use the fact that the sum of angles is 180° to write an equation.

  ∠R +∠P +∠Q = 180°

  (2x +15)° +x° +(2x +15)° = 180° . . . . substitute the known values

  5x +30 = 180 . . . . . . . . . . . . . . . . divide by °, collect terms

  5x = 150 . . . . . . . . subtract 30

  x = 30 . . . . . . . divide by 5

Then angle Q is ...

  ∠Q = (2x +15)° = (2×30 +15)°

  ∠Q = 75°

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<h3><u>Equations</u></h3>

Since when dropped, a super ball will bounce back to 80% of its peak height, continuing on in this way for each bounce, to determine an expression for the height of the nth bounce the following calculation must be performed:

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