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Alex17521 [72]
3 years ago
7

Expanding logarithmic Expression In Exercise,Use the properties of logarithms to rewrite the expression as a sum,difference,or m

ultipal of logarithms.See example 3.
In 3x(x + 1)/(2x + 1)^2
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0

Answer:

\ln{(3x)}+\ln{(x+1)}-2\ln{(2x+1)}

Step-by-step explanation:

we need to keep in mind two properties of log:

  • \ln{ab}=\ln{a}+\ln{b}
  • \ln{\dfrac{a}{b}}=\ln{a}-\ln{b}
  • \ln{a^b}=b\ln{a}

\ln{\dfrac{3x(x+1)}{(2x+1)^2}}

\ln{\left(\dfrac{3x(x+1)}{(2x+1)^2}\right)}\\\ln{(3x(x+1))}-\ln{((2x+1)^2)}\\\ln{(3x)}+\ln{(x+1)}-\ln{((2x+1)^2)}

\ln{(3x)}+\ln{(x+1)}-2\ln{(2x+1)}

this is the rewritten expression!

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The measure ∠BQS of is 80°. What is the m∠NQS? 42° 48° 128° 32°
fomenos

Answer:

m<NQS = 32°

Step-by-step explanation:

Given:

m<BQS = 80°

m<BQN = 48°

Required:

m<NQS

SOLUTION:

Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.

Therefore:

m<BQN + m<NQS = m<BQS (angle addition postulate)

48° + m<NQS = 80° (substitution)

m<NQS = 80 - 48° (Subtraction of 48 from each side)

m<NQS = 32°

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