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dybincka [34]
3 years ago
12

How to do number 6! Anyone I will cash app you

Mathematics
1 answer:
olganol [36]3 years ago
3 0

Answer:

Shawna has 50, 48,46,44 or 42 yellow pencils.

Step-by-step explanation:

Here, given the total number of pencils Shawna has  = 55 pencils

So, The number of YELLOW PENCIL + BLUE PENCIL = 55

or, Y  + B = 55

Now let us take the given cases of blue pencils one by one:

1. If she has 5 blue pencils

Here, B = 5

So, as Y  + B = 55 ⇒    Y +  5  = 55

or, Y = 5 5 - 5  = 50

Hence, Shawna has 50 yellow pencils.

2. If she has 7 blue pencils

Here, B = 7

So, as Y  + B = 55 ⇒    Y +  7  = 55

or, Y = 5 5 - 7  = 48

Hence, Shawna has 48 yellow pencils.

3. If she has 9 blue pencils

Here, B = 9

So, as Y  + B = 55 ⇒    Y +  9  = 55   ⇒  Y  = 55- 9 = 46

Hence, Shawna has 46 yellow pencils.

4. If she has 11 blue pencils

Here, B = 11

So, as Y  + B = 55 ⇒    Y +  11  = 55   ⇒  Y  = 55- 11 = 44

Hence, Shawna has 44 yellow pencils.

5. If she has 13 blue pencils

Here, B = 13

So, as Y  + B = 55 ⇒    Y +  13  = 55   ⇒  Y  = 55- 13 = 42

Hence, Shawna has 42 yellow pencils.

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The fencing William chooses costs $29.53 per foot, including installation. What will the fencing cost? Show your work.
TiliK225 [7]

Answer:

C = 29.53x

Step-by-step explanation:

Given

Unit\ cost = \$29.53

Required

The cost of fencing (C)

The cost is calculated as:

C = Unit\ Cost * Perimeter\ of fencing

Let:

x \to Perimeter\ of fencing

So, we have:

C = Unit\ Cost * x

C = 29.53 * x

C = 29.53x

<em>The question cannot be solved further since the dimension of the fence is not given</em>

<em>If you know the dimension, calculate the fence perimeter and substitute the value for x</em>

7 0
3 years ago
WE SCORED 17/22 on the test BOIS LES GOOOOOOOOOOOOOO TY FOR EVERYONE THTA HELPED YSTERDAY!!
mamaluj [8]

Answer:

Good job

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. The
Tems11 [23]

Answer:

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

They randomly survey 387 drivers and find that 298 claim to always buckle up.

This means that n = 387, \pi = \frac{298}{387} = 0.77

84% confidence level

So \alpha = 0.16, z is the value of Z that has a p-value of 1 - \frac{0.16}{2} = 0.92, so Z = 1.405.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.74

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.8

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

6 0
3 years ago
Find the area of quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21)
sasho [114]

Answer:

The area of quadrilateral ABCD is 139 unit^2.

Step-by-step explanation:

Given:

Quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21).

Now, to find the area.

The coordinates of the quadrilateral are A(1,1), B(7,-3), C(12,2), D(7,21).

So, to find the area we need to bisect the quadrilateral ABCD and get the triangles ABC and ADC and then calculate their areas:

In Δ ABC:

A(x_1,y_1)=(1,1)\:,\:B(x_2,y_2)=(7,-3)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ABC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-3-2)+(7)(2-1)+12(1--3)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-5)+(7)(1)+12(4)\right|

On solving we get:

Area\,of\,triangle\,=25.

In Δ ADC:

A(x_1,y_1)=(1,1)\:,\:D(x_2,y_2)=(7,21)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ADC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(21-2)+(7)(2-1)+12(1-21)\right|

On solving it by same process as above we get:

Area\,of\,triangle\,=114

Now, to get the area of the quadrilateral we add the areas of the triangles ABC and ADC:

25+114\\=25+114\\=139\ unit^2

Therefore, area of quadrilateral ABCD is 139 unit^2.

4 0
3 years ago
What is the dismal equivalent of 1/4
algol13

Answer:

if you mean decimal, then 1/4= 0.25

Step-by-step explanation:

hope this helped comment if ur still confused

4 0
4 years ago
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