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MAXImum [283]
3 years ago
5

What are the x-intercepts of the graph of the function f(x) = x2 + 5x − 36?

Mathematics
2 answers:
Ede4ka [16]3 years ago
6 0
Answer: Second option: (4,0) and (-9,0)

f(x)=x^2+5x-36

The x-intercepts of the graph of a function f(x) are the values of the variable x that makes f(x)=y equal to zero. To find these values we only have to equal f(x)=y to zero:
f(x)=y=0
x^2+5x-36=0

Factoring the polynomial:
(x+9)(x-4)=0

Using that if a b=0, then: a=0 or b=0
with a=x+9 and b=x-4

x+9=0 or x-4=0

Solving for x:
x+9-9=0-9 or x-4+4=0+4
x=-9 or x=4

Then the x-intercepts are the poitns (x,y)=(x,0):
(4,0) and (-9,0)
skelet666 [1.2K]3 years ago
4 0
B, is correct i just took the edgnuity unit test
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Find the equation of the line that contains the given point and the given slope. Write the equation in slope-intercept form.
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The slope-point form of a line:

y-y_0=m(x-x_0)

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y=mx+b

1.

m=6,\ (4,\ 1)\to x_0=4,\ y_0=1

Substitute

y-1=6(x-4)\qquad|\text{use distributive property}\\\\y-1=6x-24\qquad|\text{add 1 to both sides}\\\\\boxed{y=6x-23}

2.

m=-5,\ (6,\ -3)

Substitute

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3.

m=-\dfrac{1}{2},\ (-8,\ 2)\\\\y-2=-\dfrac{1}{2}(x-(-8))\\\\y-2=-\dfrac{1}{2}(x+8)\\\\y-2=-\dfrac{1}{2}x-4\qquad|\text{add 2 to both sides}\\\\\boxed{y=-\dfrac{1}{2}x-2}

4.

m=0,\ (-7,\ -1)\\\\y-(-1)=0(x-(-7))\\\\y+1=0\qquad|\text{subtract 1 from both sides}\\\\\boxed{y=-1}

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