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3 years ago

Help me factor this pls!! 49a^2−14a+1

2 answers:

7 0

You would multiply 49 by 1. After that you try to find the factors that would add to be -14 and multiply 1.
(49a-7)(49a-7)
Simplified:
(7a-1)(7a-1)

Degger [83]3 years ago

4 0

49a^2+14a+1
49a^2+7a+7a+1
7a(7a+1)+1(7a+1)
(7a+1)(7a+1)
= (7a+1)^2

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PLEASE HELP!!

Scrat [10]

Answer:

The first one B(1and 2). The second is D( 5/2)

Step-by-step explanation:

I think the first one is between 1 and 2 because if you divide 5 and 2 it will be 2 remainder 1. Then the second one is D i.e 5/2. Hope it was helpful?

5 0

3 years ago

Ainsley made a $75 deposit to her savings account.what integer represents the deposit?

Dima020 [189]

In this case, Ainsley is adding money to her savings, so the $75 deposit could be represented as the positive integer 75.

The opposite, of course, would be if Ainsley withdrew that money from her savings. In that case, we'd be subtracting money from the account, so we could use the negative integer -75 to represent that scenario.

5 0

3 years ago

Read 2 more answers

The vertices of a hyperbola are located at (3, −6) and (3, 6). The foci of the same hyperbola are located at (3,−10) and (3, 10)

lesya [120]

Answer:

The answer is A

Step-by-step explanation:

Cuz maf

5 0

4 years ago

Really easy points!!!!!! Please solve for all three answers.

katen-ka-za [31]

Answer:

1/64, 1/256, 1/1024

Step-by-step explanation:

To get from 16 to 4 we multiply by 1/4

To get from 4 to 1 we multiply by 1/4

Each time we multiply by 1/4

The next term would be 1/16 * 1/4

1/16 * 1/4 = 1/64

The take that term 1/64 and multiply by 1/4

1/64*1/4 = 1/256

Finally take 1/256 and multiply by 1/4

1/256*1/4 =1/1024

8 0

4 years ago

Help please please please please please 6th & 7th

raketka [301]

First lets start with number six. The only way to solve this is if you determine what "a" and "b" are using the first log they have given to you. $log_a_ba=\frac{1}{3}$

The first variable that I solved for was "a" and $a=e^\frac{in(b)}{2}[tex]{[tex] 0$ }

The same is also true for "b", but when you put both "a" and "b" together the only combination that I have found to work is $a=\frac{1}{2} , b=\frac{1}{4}$

Next you plug these numbers in for "a" and "b" on the second equation to get something that looks like this: $log_\frac{1}{2}_*_\frac{1}{4} (\frac{\sqrt{\frac{1}{2}}}{\sqrt[3]{\frac{1}{4}}} )= -\frac{1}{18}$ and the picture below shows where the answer becomes a negative fraction.

https://www.symbolab.com/solver/logarithms-calculator/%20%5Clog_%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B4%7D%7D%5Cleft(%5Cfrac%7B%5Csqrt%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5Cright)

If you paste that link in your search bar it will give you a even more in depth understanding of how to get this answer

Next is #7, the easier of the two.There are two ways to solve for your answers. According to the graph of this equation there are four possible real solutions. $x=2,-2,\sqrt{2}, and -\sqrt{2}$ . (This does not account for any complex solutions)