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pishuonlain [190]
3 years ago
7

Solve for each system of equations by substitution or elimination.

Mathematics
1 answer:
Tems11 [23]3 years ago
6 0

QUESTION 1

The given system of equations are:

y=x^2+5x+1

y=x^2+2x+1

We equate the two equations to get:

x^2+5x+1 =x^2+2x+1

x^2 -  {x}^{2} + 5x  - 2x = 1 - 1

3x = 0

x = 0

When x=0,

y=0^2+2(0)+1 = 1

The solution is (0,1)

QUESTION 2

The given equations are:

y=x^2-2x - 1

and

y= -x^2-2x-1

We equate both equations to get:

x^2-2x - 1 = -x^2-2x-1

Group similar terms,

x^2 +  {x}^{2} -2x  + 2x= -1 + 1

2 {x}^{2}  = 0

x = 0

We put x=0 into any of the equations to find y.

y= -0^2-2(0)-1 =  - 1

The solution is (0,-1).

QUESTION 3

The given equations are:

y=x^2+2x+1

and

y=x^2+2x-1

We equate both equations:

x^2+2x+1 = x^2+2x-1

Group similar terms:

x^2 -x^2+2x = -1 - 1

0 =  -2

This is not true.

Hence the system has no solution.

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Answer:

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Step-by-step explanation:

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