Answer:
5-46i
Step-by-step explanation:
1. Multiply (10-4i) and (4-5i), I recomnd using foil:
40-50i-16+20i^2 + (-15+20i)
2. Remove the parenthesis around -15+20i
*we can do this since there is a "+":
40-50i-16+20i^2 + (-15)+20
3. Simplify i^2
* i^2 is -1 by textbook defination:
40-50i-16+20(-1) + (-15)+20
4. Simplify
40-50i-16-20 + (-15)+20
6. Combine like terms:
-5-50i-16i+20i
5-46i
And the problem is done
<span>To find the total distance the glacier moves we must first set up the expression for rate: 22 inches/day. Next, we convert the inches into feet and we know that 12 in = 1 ft : 22 inches/day * 1 ft/12 in = 1.83 ft/day. Finally, we multiply the number of days in year (365) by the 1.83 ft/day to calculate the total distance moved: 365 days * 1.83 ft/day = 668 ft. The glacier moved 668 feet in one year.</span>
Answer:
A
Step-by-step explanation:
Because it is 2+1 and 3+0, those are the only solution, therefore A is correct
12 hours, if you multiply 50 by 12 it will give you 600 and add the 400
