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Bingel [31]
3 years ago
10

Carl is trying to determine the length of segment MN using the Pythagorean theorem.

Mathematics
2 answers:
Over [174]3 years ago
4 0

Answer:

B) Carl's answer is correct but he incorrectly labeled the leg lengths in step 2.

Step-by-step explanation:

I just took the test on edg

gavmur [86]3 years ago
3 0
B. Carl's answer is correct but he incorrectly labeled the leg lengths in step 2.
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10 points
soldi70 [24.7K]

Answer:

Here we have two inequalities.

P is price of the gallon,we have that:

$2.40 ≤ P ≤ $2.65

C is the amount of gallons that Ricardo buys each week.

8,5 ≤ C ≤ 11

Now, with this you can find the maximum and minimum amount that he can spend on a week.

The minimum is when he buys only 8.5 gallons and the price per gallon is $2.40

Cost = 8.5*$2.40 = $20.4

The maximum cost is when he buys 11 gallons, and the price of the gallon is $2.65

Cost = 11*$2.65 = $29.15

So the amount that he spends per week in gas, S, is:

$20.4 ≤ S ≤  $29.15

3 0
3 years ago
find 40% of 60 using two different strageties, one of which must include a pictorial model or digram?pls help
igor_vitrenko [27]
One way would be to convert 40% into a fraction and multiply.

40% = 2/5

2/5 * 60 = 24

Drawing a diagram could involve drawing a whole (etc. a circle) and dividing it into fifths, then shading 2 of it with each section representing 12. Hope this helps!<span />
6 0
3 years ago
Maria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there we
Delvig [45]

Answer:

Step-by-step explanation:

Let's first find the exponential function that models the situation in year one. The exponential standard form is

y=a(b)^x where a is the initial value and b is the growth/decay rate in decimal form. If it is growth it is added to 100% of the initial value; if it is decay it is taken away from 100% of the initial value. We are told that the number of cars in year one was 80 million, so

a = 80 (in millions)

If b is increasing by 10%, then we are adding that amount to the initial 100% we started with to give us 100% + 10% = 110% or, in decimal form, 1.1

The model for our situation is

y=80(1.1)^x where y is the number of cars after x years goes by. We want to find the difference between years 3 and 2, so we will use our model twice, replacing x with both a 2 and then a 3 and subtracting.

When x = 2:

y=80(1.1)^2 and

y = 80(1.21) so

y = 96.8 million cars

When x = 3:

y=80(1.1)^3 and

y = 80(1.331) so

y = 106.48 million cars

The difference between years 3 and 2 is

106.48 - 96.8 = 9.68 million cars

7 0
3 years ago
Please help!<br><br> Worth 10 points!
bonufazy [111]
10% of 140 is 14. 
to solve you first must do 10/100 = 14/x
cross multiply and you get 10x = 1400
divide 1400 by 10 and you get 140
6 0
3 years ago
Read 2 more answers
3k-2=10 whats the answer
kap26 [50]

Answer:

k = 4

Step-by-step explanation:

3k - 2 = 10

3k - 2 + 2 = 10 + 2     (adding 2 to both sides)

           3k = 12

        3k/3 = 12/3       (dividing both sides by 3)

             k = 4

Happy to help :)

4 0
2 years ago
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