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Lera25 [3.4K]
3 years ago
13

Laura was making a recipe that said the ingredients were for 6 people, but she needed to make it for 8 people. The recipe called

for 2 2/3 cups of milk and 1/4 cup of oil. How many cups of liquid ingredients did she need for 8 people?
Mathematics
1 answer:
Natalija [7]3 years ago
7 0
You can use a proportion for each ingredient.

Milk:
2 2/3 cup are to 6 people as x cups are to 8 people

(2 2/3)/6 = x/8

(8/3)/6 = x/8

6x = 8 * 8/3

6x = 64/3

x = 32/9 = 3 5/9

3 5/9 cups of milk

Oil:
1/4 cup is to 6 people as x cups are to 8 people

(1/4)/6 = x/8

6x = 8 * 1/4

6x = 2

x = 2/6 = 1/3

1/3 cup of milk
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Nataly [62]

Hi there! My Name is Alex! The Answer to your question is listed Below Hope this helps!

Answer:

y=-\frac{1}{6} x+3\\

How to Solve For Slope Intercept Form...

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Please Help Me! It would be very appreciated if you did this ASAP,thank you!
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Answer:

m/_2 = 127°

m/_4 = 127°

m/_1 = 53°

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Step-by-step explanation:

angle 2 and 4 are the same in the diagram.

to get angle 1 and 3 i did:

127°×2°=254°

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2 years ago
The distribution of the weights of loaves of bread from a certain bakery follows approximately a normal distribution. Based on a
artcher [175]

Answer:

μ=23.710740....

σ=3.592592....

Step-by-step explanation:

At first, we are told that it´s a normal distribution and the following:

P(x≤15.34)=0.1

P(x≤16.31)=0.2

We start looking for those values (0.1 and 0.2) and the probabilities that gives us those values in a normal standard distribution. There´s some tools that´ll help us out but i´ll be using a chart with the values of some probabilities in a normal standard distribution (That it´s attached).

The probability of P(z≤ a.b) where "a" is the whole part of a number and "b" the decimal part is in the coordinates (a,b). For example for our problem:

P(z≤-2.33)=0.099≈0.1

P(z≤-2.06)=0.197≈0.2

To find a probability of a normal (not standard) distribution we use a method called Normalize that proceeds:

P(x≤a)=P( (x-μ)/σ ≤ (a-μ)/σ )

Where μ is the Mean of the data and σ is the Standard deviation. P( (x-μ)/σ ≤ (a-μ)/σ ) is now part of a normal standard distribution and we are able to look for it in the chart.

We will use it to find the Mean and the STD for our distribution.

P(x≤15.34)=P(z≤-2.33)≈0.1

P(x≤16.31)=P(z≤-2.06)≈0.2

so we have the equations:

(15.34 - μ)/σ= -2.33 and (16.31 - μ)/σ= -2.06

And we solve them for μ and σ:

(15.34 - μ)/-2.33= σ and (16.31 - μ)/-2.06= σ

(15.34 - μ)/-2.33 = (16.31 - μ)/-2.06

2.06*(15.34 - μ) = 2.33(16.31 - μ)

2.33μ - 2.06μ = 2.33(16.31) - 2.06(15.34)

μ= 6.4019 / 0.27

μ= 23.710740...

With this value we find σ in one equation:

(15.34 - (23.710740...)/σ = -2.33

(15.34 - (23.710740...)/-2.33 = σ

σ=3.592592...

We finally have our answers:

μ=23.710740....

σ=3.592592....

3 0
3 years ago
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