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3 years ago

Please help I'm stuck on these 2 problems would help so much!! Thanks!

Mathematics

1 answer:

MrRa [10]3 years ago

4 0

700 - 100 =600 she spent $600 worth of monthly payments. if there is 12 months in a year then 600 ÷ 12 = 50 so she spent $50 a month.

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A dolphin jumps from the water at an initial velocity of 16 feet per second. The equation h + -16t^2 + 80t models the dolphin's

Dominik [7]

Answer:

100feet

Step-by-step explanation:

Given the height reached by a dolphin expressed by the equation is h = -16t^2 + 80t. At maximum height, the velocity is zero, hence;

v(t) = dh/dt = -32t + 80

0 = -32t + 80

32t = 80

t = 80/32

t = 2.5secs

Substitute t = 2.5 into the height formula h = -16t^2 + 80t

h = -16(2.5)^2 + 80(2.5)

h = -100+200

h = 100feet

Hence the maximum height the dolphin jumps is 100feet

3 0

2 years ago

!!!!!!!!!!!!help me

steposvetlana [31]

Answer:

Step-by-step explanation:

i'll do a few of them

1) one inch plus a half inch plus an eighth inch plus a sixteenth inch

1 + 1/2 + 1/8 + 1/16 read the tick marks

1 + 8/16 + 2/16 + 1/16 find a common denominators

1 and 11/16 add the sixteenth numerator

4) 6 inch plus an eighth inch plus a sixteenth inch

6 + 1/8 + 1/16 read the tick marks

6 + 2/16 + 1/16 find a common denominators

6 and 3/16 add the sixteenth numerator

5) nine inch plus a quarter inch plus an eighth inch

9 + 1/4 + 1/8 read the tick marks

9 + 2/8 + 1/8 find a common denominators

9 and 3/8 add the sixteenth numerator

5 0

3 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago

The numerator of a certain fraction is four times the denominator. If 10 is added to both numerator and denominator the resultin

Ronch [10]

20/5 4x/x adding 10 to each 4x+10/x+10 =2 Multiple x+10 to each side 4x+10=2x+20 Then subtract and get 2x=10 Divide X=5 Now plug it back in 20/5

7 0

3 years ago

How do you write 2 thousands plus 12 hundreds in standard form

mamaluj [8]

The standard for is 2000+ 1200

6 0

3 years ago

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