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dimaraw [331]
3 years ago
9

Quickly plzzz F=3. G=-4. H=5. Evaluate equation plzz

Mathematics
1 answer:
Mumz [18]3 years ago
4 0

Answer:

-4

Step-by-step explanation:

| f+g| - h

F=3. G=-4. H=5.

| 3 + -4| -5

| -1| -5

The absolute value of -1 is 1

1 -5

-4

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Write the expression using rational exponents. Then simplify and convert back to radical notation.
ioda

Answer:

The radical notation is 3x\sqrt[3]{y^2z}

Step-by-step explanation:

Given

\sqrt[3]{27 x^{3} y^{2} z}

Step 1 of 1

Write the expression using rational exponents.

\sqrt[n]{a^{m}}=\left(a^{m}\right)^{\frac{1}{n}}

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$(a \cdot b)^{r}=a^{r} \cdot b^{r}:(27)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$

=$(3^3)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$

$=\left(3\right)\left(x}\right)} \cdot\left(y}\right)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

Simplify $3 x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3 x \sqrt[3]{y^{2} z}$

Learn more about radical notation, refer :

brainly.com/question/15678734

4 0
3 years ago
Expain the diffents between numerical expressions and algebraic expressions
Oduvanchick [21]
<h2>Numerical expressions are numbers and signs, like below.  The following are some examples of numerical expressions, numerical expressions do not use letters. 4 + 20 – 7, (2 + 3) – 7, (6 × 2) ÷ 20, 5 ÷ (20 × 3)   An algebraic expression uses letters and it says you to find "x/y/z". Example; 4+20xy-7x, (2x+3) - 7y+20.</h2>
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3 0
3 years ago
A granola bite contains 27 calories. Most of the calories come from grams of carbohydrates. The rest come from other ingredients
GuDViN [60]

Step-by-step explanation:

Given the expression that modeled the relationship between these quantities (calories from grams of carbohydrate and the rest of the ingredients) as

4c+5 = 27

From the equation, the constant value of 5 represents the calories in grams of  the rest of the ingredients present in the bite.

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This means that the total calories of carbohydrate the granola bite contains is 4(5.5) i.e 21 calories of carbohydrate

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7 0
3 years ago
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Dafna1 [17]

Answer:

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8 0
3 years ago
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