Question

Find three consecutive odd integers such that the difference between four times the largest and twice the middle integer is -10.

Answer 1

Answer:

The integers are:  -11 -9, -7

Step-by-step explanation:

odd integers are spaced 2 units apart each, so if we let the smallest be "x", the next one would be "x + 2", and the next one "x + 4".

These are our 3 consecutive integers:

x

x + 2

x + 4

Given,

Difference between 4 times LARGEST and TWICE MIDDLE is -10, so we can write:

4(x+4) - 2(x+2) = -10

Now, we solve for x using algebra:

$4(x+4) - 2(x+2) = -10\\4x+16-2x-4=-10\\2x+12=-10\\2x=-10-12\\2x=-22\\x=-11$

So, the smallest is -11, others will be -9 and -7

The integers are:  -11 -9, -7