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4 years ago

For questions 1 – 3, use the following partial class definitions:

Computers and Technology

1 answer:

Ratling [72]4 years ago

6 0

Answer:

QUESSTION 1: B

QUESTION 2: C

QUESTION 3: D

Explanation:

In question 1, since A3 extends A2, it implies A3 is the subclass of A2 and A2 is its super class, same applies to the relationship between A1 and A2, the extends keyword is used to indicate inheritance in the child class (subclass)

In question 2, the class A2 has two declared instance variables (a,b) It has also inherited the public variables of its superclass (A1) so it has the x,z (Inherited variables) and a,b (its own variable)

The same explanation in question 2 applies to question three. The Class A3 has access to all the public fields of A1 and A2 as well as its own declared field x,z,a (Inherited public fields) q Its own field.

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Answer:

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3 years ago

In an experiment, the temperature of a liquid at 16.9 degrees Celsius is decreasing at a rate of 2.3

Damm [24]

Answer:

The number of minutes it will take for a liquid and a solid to reach the same temperature is 3 minutes.

Step-by-step explanation:

You know that the temperature of liquid at 16.9°C is decreasing at a rate of 2.3°C per minute. Then, the temperature of the liquid after t minutes, as its value decreases, will be the difference between the initial temperature of 16.9 ° C and the temperature after t minutes. So:

temperature of the liquid= 16.9°C - 2.3 °C/minute * t

On the other side, you know that the temperature of a solid at 30.7°C is decreasing at a rate of 6.9°C per minute. Then, the temperature of the solid after t minutes, as its value decreases, will be the difference between the initial temperature of 30.7°C and the temperature after t minutes. So:

temperature of the solid= 30.7°C - 6.9 °C/minute * t

You want to calculate the number of minutes it will take for a liquid and a solid to reach the same temperature. This is:

temperature of the liquid= temperature of the solid

16.9°C - 2.3 °C/minute * t= 30.7°C - 6.9 °C/minute * t

Solving:

- 2.3 °C/minute * t= 30.7°C - 6.9 °C/minute * t - 16.9°C

- 2.3 °C/minute * t + 6.9 °C/minute *t= 30.7°C - 16.9°C

4.6 °C/minute * t = 13.8 °C

t=3 minutes

So the number of minutes it will take for a liquid and a solid to reach the same temperature is 3 minutes.

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