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blsea [12.9K]
3 years ago
15

Question #2

Computers and Technology
2 answers:
Gekata [30.6K]3 years ago
8 0

Answer:

C.

Explanation:

mukhang

letter

C.

pambihira

ka

naman

bat

hindi

ka

magtanong

sa

mga

nakakatanda

mong

kapatid

igor_vitrenko [27]3 years ago
6 0

Answer:

The answer to your question is C. Have a wonderful safe day. <3 <3 <3

Explanation:

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What Windows Server 2016 edition is used for volume licensing customers in academic markets and allows multiple users to share o
Lunna [17]

Answer:

The correct answer to the following question will be Option D (Data Center).

Explanation:

Data centers are essentially clustered areas where computer and networking infrastructure is focused to gather, store, process, transmit or allow endless supplies of data.

Windows Server 2016 is released in three versions (Microsoft for Windows Server 2016 no longer provides a base version as it has been in Windows Server 2012):

  • Standard
  • Essentials
  • Data center

With a large number of integrated environments, the Data center is suitable for all organizations for heavy IT workload criteria.

Therefore, Option D is the right answer.

6 0
4 years ago
Write a program that sorts an array of 10 integers using bubble sort. In the bubble sort algorithm, smaller values gradually “bu
blsea [12.9K]

Answer:

#include<iostream>

using namespace std;

int main(){

   //initialization

  int arr1[10] = {2,4,6,1,7,9,0,3,5,8};

  int temp;

   int size_arr;

   //nested for loop

  for(int i=0;i<size_arr-1;i++){

   for(int j=0;j<size_arr-i-1;j++){

       if(arr1[j]>arr1[j+1]){ //compare

               //swapping

           temp = arr1[j];

           arr1[j]=arr1[j+1];

           arr1[j+1]=temp;

       }

   }

  }

  //display the each element

  for(int i=0;i<10;i++){

   cout<<arr1[i]<<" ";

  }

    return 0;

}

Explanation:

Create the main function and declare the variable and defining the array with 10 values.

take the nested for loop, nested loop means loop inside another loop.

the outer loop traverse in the array from 0 to size-1.

and inside loop traverse from 0 to size -i-1, because for every cycle of the outer loop the one element is sorted at the end. so, we do not consider the element from the last for every cycle of the outer loop. That's why (size-i-1)

In the bubble sort, the first element compares with the second element and if the first id greater than the second then swap the value. so, for the above algorithm, we take the if statement and it checks the condition if the condition becomes true then the swap algorithm executes.

we take a third variable for swapping. after that, if the outer loop condition false it means all elements will traverse and then the loop will terminate.

and finally, take another for loop and display the output.

8 0
4 years ago
Write a method transpose, that takes as argument a 2D array of integers, myTable, and returns the transpose of myTable. The tran
Gelneren [198K]

Answer:

The program to this question can be given as:

Program:

import java.util.*; //import package

public class Main //defining class

{

public static int[][] transpose(int[][] a1) //defining function transpose

{

int i,j; //define variables

int[][] transpose = new int[a1[0].length][a1.length]; //define variable transpose.

//loop for transpose matrix.

for(i = 0; i < a1.length; i++)  

{

for(j = 0; j < a1[i].length; j++)

{

transpose [j][i] = a1[i][j]; //hold value in transpose variable

}

}

return transpose ; //return transpose matrix.  

}

public static void main(String[] args) //main method.

{

int row,col,i,j; //defining variable.

Scanner obj = new Scanner(System.in); //creating Scanner class Object

System.out.print("Enter number of rows: ");//message

row = obj.nextInt(); //input rows form user.

System.out.print("Enter number of columns: ");//message

col = obj.nextInt(); //input columns form user.

int[][] a1 = new int[row][col]; //defining array.

System.out.println("Enter matrix"); //message

// loop for input array elements from user

for(i=0; i<a1.length;i++)  

{

for(j=0; j<a1[i].length;j++)  

{

a1[i][j]=obj.nextInt(); //input in array variable.

}

}

System.out.println("Matrix you insert :"); //message

// loop for display array.

for(i=0; i<a1.length;i++)  

{

for(j=0; j<a1[i].length;j++)  

{

System.out.print(a1[i][j]+" "); //print matrix

}

System.out.print("\n");

}

int[][] result = transpose(a1); //define result array variable that holds function value.

System.out.println("Transposed matrix is :");

//use loop for print Transpose matrix.

for(i = 0;i < result.length;i++)

{

for (j = 0; j < result[i].length;j++)

{

System.out.print(result[i][j] + " "); //print matrix

}

System.out.print("\n");

}

}

}

Output:

Enter number of rows: 2

Enter number of columns: 3

Enter matrix

2

3

4

9

8

7

Matrix you insert :

2 3 4  

9 8 7  

Transposed matrix is :

2 9  

3 8  

4 7  

Explanation:

The description of the above program can be given as:

  • In the above program firstly import a package, then declare a class that is "Main" inside a class defining a transpose() function this function returns a matrix in transpose form.
  • In the main class, we define a variable and matrix that is "row, col, i, j and a1[][]".  Then we Creating a scanner class object, which is used by row, col and a1[][] variables for user input.  
  • The row and col variables are used to declare matrix size and i, j variable is used in the loop for insert and display matrix.  
  • a1[][] matrix is used for input matrix elements and passes into transpose() function as an argument that returns a value that is held in the result variable. This is used as a loop for the print transpose matrix.

5 0
4 years ago
The K-Means algorithm terminates when:_______
gavmur [86]

Answer:

b. the cluster centers for the current iteration are identical to the cluster centers for the previous iteration.

Explanation:

K-mean algorithm is one of the mot widely used algorithm for partitioning into groups of k clusters. This is done by partitioning observations into clusters which are similar to each other. When using k-mean algorithm, each of the different clusters are represented by their centroid and each point are placed only in clusters in which the point is close to cluster centroid.

The K-Means algorithm terminates when the cluster centers for the current iteration are identical to the cluster centers for the previous iteration.

7 0
4 years ago
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