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pickupchik [31]
4 years ago
9

write a linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) site

Mathematics
1 answer:
olchik [2.2K]4 years ago
8 0

A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:

y=\frac{1}{4}x-\frac{9}{4}

Step-by-step explanation:

Given points are:

(-11, -5) = (x1,y1)

(1, -2) = (x2,y2)

We have to find the slope first

m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-2-(-5)}{1-(-11)}\\m=\frac{-2+5}{12}\\m=\frac{3}{12}\\m=\frac{1}{4}

Slope-intercept form is:

y=mx+b

Put the value of slope

y=\frac{1}{4}x+b

To find the value of b, putting the point (1 -2) in equation

-2=\frac{1}{4}(1)+b\\-2=\frac{1}{4}+b\\-2-\frac{1}{4}=b\\b=\frac{-8-1}{4} \\b=\frac{-9}{4}

Putting the values of b and m

y=\frac{1}{4}x-\frac{9}{4}

A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:

y=\frac{1}{4}x-\frac{9}{4}

Keywords: Equation of line, slope-intercept form

Learn more about equation of line at:

  • brainly.com/question/4767370
  • brainly.com/question/4770453

#LearnwithBrainly

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