Answer:
The correct option is B.
Step-by-step explanation:
Given information: AB\parallel DCAB∥DC and BC\parallel ADBC∥AD .
Draw a diagonal AC.
In triangle BCA and DAC,
AC\cong ACAC≅AC (Reflexive Property of Equality)
\angle BAC\cong \angle DCA∠BAC≅∠DCA ( Alternate Interior Angles Theorem)
\angle BCA\cong \angle DAC∠BCA≅∠DAC ( Alternate Interior Angles Theorem)
The ASA (Angle-Side-Angle) postulate states that two triangles are congruent if two corresponding angles and the included side of are congruent.
By ASA postulate,
\triangle BCA\cong \triangle DAC△BCA≅△DAC
Therefore option B is correct
Answer:
4/1/4
Step-by-step explanation:
48÷6
=8-3 3/4
=4/1/4
For this case we have the following quadratic equation:

Where:

By definition, the discriminant of a quadratic equation is given by:

We have to:
Two different real roots
Two different complex roots
Two equal real roots
Substituting the values we have:

So, we have two different complex roots
Answer:
Two different complex roots
The answer is whole
Hope this helps
Answer:

Step-by-step explanation:
Given


Find h(x)
Substitute -7 for x


Absolute values return positive. So:

