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boyakko [2]
3 years ago
10

F(x) = e^x/2 Find F(0). 1.36 1 0

Mathematics
2 answers:
Lelu [443]3 years ago
8 0

Answer:

f(0)

= e^o/2

= 1/2

=0.5 it is the required answer

Natasha2012 [34]3 years ago
5 0

Answer:

1

Step-by-step explanation:

Replace the variable x with 0 in the expression.

F(0) = e^^\frac{0}{2}

Simplify the result.

Divide 0 by 2.

F(0) = e^0

Anything raised to 0 is 1.

F(0) = 1

The final answer is 1.

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___________ is a standard of measure for a physical quantity and is included as part of the x and y axes labels on a line graph.
zlopas [31]

Answer:

Unit of measure

Step-by-step explanation:

Unit of measure

When we construct any type of graph the unit of measure needs to be present, becuase the numbers without units are just numbers and with just the numbers we can't have physical interpretation of the situation.

For this reason is importatn to include the units of meausre with the plots since with that we have a point of reference for the variables used.

And satisfy the condition "A standard of measure for a physical quantity and is included as part of the x and y axes labels on a line graph."

8 0
3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
Solve x/10 = -7<br><br>a.x=-70<br>b.x=-0.7<br>c.x=3<br>d.x=-17​
Brums [2.3K]

The answer is A. x=-70.

8 0
3 years ago
HElPP<br> what is 232 if it's scaled down by a factor of 1/10
Lynna [10]

Answer:

23.2

Step-by-step explanation:

Scaling down by a factor of 1/10 is equal to dividing the number by 10.

So 232 getting scaled down by a factor of 1/10 is equivalent to 232/10 i.e. 23.2.

3 0
3 years ago
Explain how you can find the center of dilation of a triangle and its dilation.
Naddika [18.5K]

In mathematics, the term "center of dilation" refers to a constant point on a surface from which all other points are either enlarged or compressed. The center of dilation and the scale factor comprise the two properties of a dilation.

4 0
3 years ago
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