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butalik [34]
3 years ago
14

Which of the following relations is a function?

Mathematics
2 answers:
kolbaska11 [484]3 years ago
7 0
The answer to your question is b

Klio2033 [76]3 years ago
5 0
A.\\(\boxed{3}, 1),\ (-3, 4),\ (-5, 1)\, (\boxed{3}, -5)-NO\\\\B.\\(-5, 1),\ (-3, -5),\ (3, 5)\, (6, 1)-YES\\\\C.\\(\boxed{-5}, 4),\ (-3, 6),\ (\boxed{-5}, 3),\ (6, 2)-NO\\\\D.\\(-5, 1),\ (\boxed{-3}, 4),\ (3, -5),\ (\boxed{-3}, 6)-NO
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What is 5.95 × 106 written in standard form? A. 595,000 B. 59,500 C. 5950 D. 5,950,000
tiny-mole [99]
The answer is option D "<span>5,950,000".

</span>5.95 * 10^6 = &#10;&#10;5 9 5 0 0 0 0/&#10;1 2 3 4 5 6

Which would equal 5,950,000.

Hope this helps!
7 0
3 years ago
Why in the world did I have nearly 800 points worth of questions deleted? Every single one of them were right! What do I do now?
vekshin1

Answer:

read your username :)

Step-by-step explanation:

5 0
3 years ago
Which point is the image of point R(4, -7) first reflected across the x-axis and then across the y-axis?
nasty-shy [4]

Answer:

(-4, 7)

Step-by-step explanation:

It would be the exact opposite of point R because it was rotated about 180 degrees from it's original location

6 0
2 years ago
Please do step by steps for each!
Schach [20]

Answer:

  • x² - 8x + 12
  • x³ + 2x² - 15x - 36
  • x³ -2x² - 15x

Step-by-step explanation:

#1) Find the polynomial with roots at 2 and 6

  • (x -2)(x - 6) = x² - 8x + 12

#2) Find the polynomial with a double root at -3 and another root at 4

  • (x+3)(x+3)(x-4) = (x²+6x+9)(x-4) = x³ + 2x² - 15x - 36

#3) Find the polynomial with roots 0, -3 and 5

  • (x -0)(x+3)(x-5) = x(x²-2x - 15) = x³ -2x² - 15x
3 0
3 years ago
Evaluate g(3) if g(x) = 2x + 1.<br> 0 1<br> 07<br> 24
evablogger [386]

Answer:

g(3) = 7

Step-by-step explanation:

g(3) means to substitute "x" for 3.

Change any "x" in the function to 3. Then solve.

Take the function

g(x) = 2x + 1

Substitute x = 3

g(3) = 2(3) + 1

Solve with BEDMAS order (brackets, exponents, division, multiplication, addition, subtraction).

g(3) = 2(3) + 1           Multiply first

g(3) = 6 + 1          Add

g(3) = 7               Answer

5 0
3 years ago
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