Answer:
2
Step-by-step explanation:
10/3 times 6 =20
1/4 (20) -3
Use PEMDAS
1/4 (20) is 5
5-3=2
Answer:
at least 9 students in each cohort.
Step-by-step explanation:
Given that :
In a class, there are 25 students and each of them is either a sophomore, a freshman or a junior. We have to determine the number students in the same cohort.
Let us suppose there are equal number of students in each of the cohort.
Now let us assume that the number of the students in each cohort be 8, i.e. each as a freshman, a junior or a sophomore. Therefore, the total number in the all the cohorts will be 24 students only.
Thus, we can say that there are at least
freshman, at least
sophomore or at least
junior in each of the cohort.
Answer:
The greater value of the given set is 98.43.
Explanation:
Here the units of the distance given for all the data is miles(mi).
So, the greater value is that value which has higher magnitude.
Values are 79.47,54.28,65.5 and 98.43
Values in their increasing order is given by
54.28 < 65.5 < 79.47 < 98.43
Values in their decreasing order is given by
98.43 > 79.47 > 65.5 > 54.28
So, the greater value of the given set is 98.43.
Answer: 8H=T
Step-by-step explanation:
8 is dependant on the hours so you put it together. Your independent
value is T since it is by itself. So your answer becomes.
8H=T
Answer:
Step-by-step explanation:
a) ΔACD ~ ΔABE so the ratios of corresponding sides are the same. That is ...
CD/BE = CA/BA
CD/3.8 = 12.3/8.2
CD = 3.8×12.3/8.2 = 5.7 . . . . cm
__
b) As above, the ratios of corresponding sides are the same.
ED/AD = BC/AC
ED/9.15 = (12.3-8.2)/12.3 . . . . BC = AC - AB
ED = 9.15×4.1/12.3 = 3.05 . . . . cm