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9966 [12]
2 years ago
8

Two people play a game. The first person starts with the number 1 and can multiply 1 by any number from 2-9. Then, the second pe

rson multiplies this new number by any number from 2-9. The winner is the first person to get a million or more. Who wins the game with an optimal strategy?
Mathematics
1 answer:
Maru [420]2 years ago
8 0

Answer: player number one

Step-by-step explanation:

Player number one starts with one and then he waits for player number two.

It doesnt matter what player number two makes, he needs to keep his multipliyer in two until player two pasess one millon/9 =111111.11 for the first time, then, he plays 9.

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Zoe's will leave a 15% percent tip .

Step-by-step explanation: 2.00  


5 0
3 years ago
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After my salary was increased by $16\%,$ it was $\$52{,}200$. What was my salary before the increase?
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The salary before the increase was $48000.
5 0
2 years ago
What is the solution to this equation?
HACTEHA [7]

Answer:

Option 1 - X = 9

Step-by-step explanation:

The solution to this equation, x - 15 = - 6

Solving the following,

Step 1: x - 15 = -6

Replace all the numerical values in one side and x digits on the other side

Step 2: x = -6+15

Step 3: x = 9

Therefore, the value of x is 9.

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3 years ago
The coldest temperature recorded on the surface of a planet was - 248 Celsius is the warmest temperature recorded on the surface
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7 0
2 years ago
A The length of a rectangle is 4 m more
Lady bird [3.3K]

Given :

  • The length of a rectangle is 4m more than the width.
  • The area of the rectangle is 45m²

⠀

To Find :

  • The length and width of the rectangle.

⠀

Solution :

We know that,

\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

\qquad \sf \: { \dashrightarrow x  \times  (x - 4) = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x - 45 = 0 }

\qquad \sf \: { \dashrightarrow {x}^{2}    - 9x+ 5 x - 45 = 0 }

\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }

\qquad \sf \: { \dashrightarrow (x  - 9) (x  + 5) = 0 }

\qquad \sf \: { \dashrightarrow x = 9, \: \: x =  - 5}

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:

\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:

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