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3 years ago

Can you help me solve number 4 and please show your work

Mathematics

1 answer:

anastassius [24]3 years ago

4 0

Answer:

See diagram below. This is a relation and not a function.

Step-by-step explanation:

An arrow diagram has two ovals - one for x -values and one for y-values. Inside the ovals, all values ONLY appear ONCE and generally from least to greatest. Then draw an arrow from each value to its matching value from input to output according to the table.

Be sure to draw two ovals around the lists below:

Inputs Outputs

1 ----------------> 2

11 -----------------> (POINTS DIAGONAL TO 2)

15 -----------------> 12

16 ------------------> 32

This is not a function because each output must only match to one input. The output 2 matches to both 1 and 11. This is a relation.

You might be interested in

when a number is added to 1/5 of itself, the result is 24. the equation that models this problem is n 1/5 n = 24. what is the va

GuDViN [60]

Let n be unknown number, then 1/5 of this number is 1/5n. When you add these two numbers, you get

$n+\dfrac{1}{5} n.$

You know that this sum is equal to 24, so

$n+\dfrac{1}{5} n=24.$

1. Multiply this equation by 5:

$5n+n=120.$

2. Solve it:

$6n=120,\\n=120:6,\\n=20.$

Answer: n=20, correct choice is B.

4 0

3 years ago

Read 2 more answers

Write the phrase as an expression. Then evaluate when y=20.

alisha [4.7K]

Answer:

$Q=\frac{40}{y-16}$

$Q=10$

Step-by-step explanation:

Let the quotient be represented by 'Q'.

Given:

The difference of a number 'y' and 16 is $y-16$

Quotient is the answer that we get on dividing two terms. Here, the first term is 40 and the second term is $y-16$ . So, we divide both these terms to get an expression for 'Q'.

The quotient of 40 and $y-16$ is given as:

$Q=\frac{40}{y-16}$

Now, we need to find the quotient when $y=20$ . Plug in 20 for 'y' in the above expression and evaluate the quotient 'Q'. This gives,

$Q=\frac{40}{20-16}\\Q=\frac{40}{4}=10$

Therefore, the quotient is 10, when the value of 'y' is 20.

7 0

4 years ago

Can anyone figure this out?

Verizon [17]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill$

$\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}$

now that we know how long each one is, let's plug those in Heron's Area formula.

$\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18$

5 0

4 years ago

What is the volume of this solid figure made with cubes?

Vadim26 [7]

Answer:

15 cubic units

Step-by-step explanation:

Use multiplication (V = l x w x h) to find the volume of a solid figure.

3*5=15

3 0

3 years ago

I NEED HELP PLEASE !!!!!!

elena-14-01-66 [18.8K]

Answer:

5/6 , - 5/6

Step-by-step explanation:

square root it

6 0

3 years ago