The angle is 127°, so the Pythagorean theorem does not apply.
Generally, you would use the Law of Cosines to solve for the third side when given two sides and the angle between them.
EF^2 = 7^2 +15^2 -2*7*15*cos(127°)
EF ≈ √(400.3812) ≈ 20.00953
My guess is that you're expected to use 20 for the length of the 3rd side.
By Heron's formula, s = (7 +15 +20)/2 = 21
Area = √(21*(21 -7)*(21 -15)*(21 -20)) = √(21*14*6*1) = √1764 = 42 . . . . yd^2
_____
More directly,
.. Area = (1/2)*7*15*sin(127°) ≈ 41.928 . . . . yd^2
Answer:
c times 6 equals 96
Step-by-step explanation:
<u>Answer-</u>
<em>For </em><em>side length of 3.56 cm</em><em> and </em><em>height of 7.10 cm</em><em> the cost will be minimum.</em>
<u>Solution-</u>
Let us assume that,
x represents the length of the sides of the square base,
y represent the height.
Given the volume of the box is 90 cm³, so

As the top and bottom cost $0.60 per cm² and the sides cost $0.30 per cm². Total cost C will be,

Then,

As C'' has all positive terms so, for every positive value of x (as length can't be negative), C'' is positive.
So, for minima C' = 0

Then,



Therefore, for side length of 3.56 cm and height of 7.10 cm the cost will be minimum.
Answer:
13:7
Step-by-step explanation:
If you divide each number (6.5 and 3.5) by .5
6.5/.5=13
3.5/.5=7