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erastova [34]
3 years ago
14

Will the Brainliest answer!!! solve for x and y. 946x+642y=911

Mathematics
2 answers:
Ronch [10]3 years ago
8 0

While you cannot solve 946x+642y=911 for numerical values of x and y, you can indeed solve 946x+642y=911 first for x and then for y:

-911 - 642y

For x: 946x+642y=911 becomes 946x = 911 - 642y, or x = ------------------

946

911-946x

For y: 946x+642y=911 becomes 642y = 911-946x, or y = ---------------

642

trasher [3.6K]3 years ago
5 0

This is one of the Diophantine equations. The solution is usually positive integers. This is an exception. It either requires fractions (I hope not) or negative numbers.


So let's see what we have.


Let's start with some obvious statements.

Is there any kind of integer that will solve this? My inclination is to say no. 911 is an odd number. How can 2 evens be manipulated to give an odd? No way using integers that I know of. So it looks like there are an infinite number of real solutions but no integers.


946x+642y=911


Is there any common factor to each of the numbers? Put another way, is 911 prime? The other two are not. 911 is prime. Our next step is to graph it. Maybe that will tell us something. We get the x and y intercepts, but nothing near an answer. You can go to desmos yourself and put this graph in. Just click on any point that looks reasonable to you. They are all give at least 1 decimals.


I think your teacher is just trying to work with awkward numbers. So work with awkward numbers. You could always just put in say 3 for x and solve for y.

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The history museum is hosting a special exhibition on history of flight. The admission ticket for each adult costs $7 and the ad
stiks02 [169]

Answer:

Use simultaneous equation for this problem

y= number of adults

x = number of children

3y + 2x = 160

y + x = 60

then we double the second equation

3y + 2x = 160

2y + 2x = 120

we cancel x by elimination

3y - 2y = 160 - 120

y = 40

Step-by-step explanation:

hope this helps

5 0
2 years ago
Given that x overbarequals3.6667​, s Subscript xequals2.0656​, y overbarequals4.2167​, s Subscript yequals1.5613​, and requalsne
Shtirlitz [24]

Answer:

y = 0.7063x+2.7790

Step-by-step explanation:

Given that

x bar = 3.6667\\s_x= 2.0656\\y bar = 4.2167\\s_7 = 1.5613\\r = -0.9344

We have slope of linear regression line is

a=r*\frac{s_y}{s_x} =0.9344(\frac{1.5613}{2.0656} )\\=0.7063

So regression line would be of the form

y-4.2167 = 0.7063(x-2.0656) (since it passes through xbar, y bar)

y = 0.7063x+2.7790

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6 0
3 years ago
The question is below
Ad libitum [116K]

Answer:

£59.25

Step-by-step explanation:

Hello!

To solve this problem, we must:

  1. Solve for the length of the fence (aka height)
  2. Find the area of the lawn (trapezoid)
  3. Find the number of cans needed
  4. Find the price of all the cans

Area of a trapezoid, and why the formula works:

A trapezoid is a quadrilateral with one set of parallel sides known as bases. The other two sides are known as the legs.

To find the area of a trapezoid, we use the formula:

\frac{B_1 + B_2}{2}* h

This works because if we used the formula, we would be duplicating the trapezoid to form a rectangle with a side length of B1 + B2, and a height of h. Since the trapezoid is half of that, we divide by 2.

Solve for height:

The height is unknown but can be found using the Pythagorean Theorem.

The difference between the bases is the length of the bottom leg of the right triangle, and 17 is the hypotenuse.

Difference = 20 - 12 = 8

Hypotenuse = 17

  • 8² + fence² = 17²
  • 64 + fence² = 289
  • 225 = fence²
  • fence = 15

The height is 15

Solve for area:

Now we can solve for the area.

  • A = \frac{B_1 + B_2}{2} * h
  • A = \frac{12 + 20}{2} * 15
  • A = \frac{32}{2} * 15
  • A = 16 * 15 = 240

The area is 240

Cans:

The area of the lawn is 240 square meters. Each can cover 100 square meters.

  • 240 ÷ 100 = 2.4

Since we can't use part of a can, we round up to three whole cans.

The price of 3 cans :

  • 3 * 19.75
  • 59.25

£59.25

The Pythagorean Theorem:

The Pythagorean theorem is a very common geometry formula used to find the length of the hypotenuse in a right triangle, given the lengths of the two other bases.

The formula is : a^2 + b^2 = c^2

  • a is a leg
  • b is a leg
  • c is the hypotenuse

Images attached for your reference

7 0
2 years ago
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