80 degrees. 145 = (4x+5) + (6x-10) = 10x-5... so 10x = 150, x = 15. LMN = 6x-10 = 6(15) - 10 = 80.
Step 1
<span>Calculate the error
</span>error=75-64-----> 11 ft
step 2
<span>Divide the error by the exact value
</span>11/64=0.1719
step 3
<span>Convert that to a percentage
</span>0.1719*100=17.19%
the answer is
17.19%
Answer: 0.0668073
Step-by-step explanation:
Given : The number of miles each tire lasts before it completely wares out follows a normal distribution with mean μ = 50,000 miles and standard deviation σ = 8,000 miles.
Let x be the random variable that represents the number of miles each tire lasts.
z-score : 
For x= 62,000

By using the standard z-value table , the probability for a randomly selected tire to last for at least 62,000 miles will be :_

Hence, the probability for a randomly selected tire to last for at least 62,000 miles = 0.0668073