Answer:
△ AMC ≅ △ BMC ⇒ proved down
Step-by-step explanation:
Let us revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles and one side in the 2nd Δ
- HL ⇒ hypotenuse and leg of the 1st right Δ ≅ hypotenuse and leg of the 2nd right Δ
In Δ ABC
∵ CM ⊥ AB
∴ m∠AMC = m∠BMC = 90°
∴ ∠1 ≅ ∠2
In the two triangles AMC and BMC
∵ ∠1 ≅ ∠2 ⇒ proved
∵ ∠3 ≅ ∠4 ⇒ given
∵ CM is a common side in the two triangles
∴ CM ≅ CM ⇒ common side
→ Two angles and the side joining them in the 1st triangle ≅ two angles
and the side joining them in the 2nd triangle, then use the 3rd case
of congruency above
∴ Δ AMC ≅ Δ BMC ⇒ by using ASA postulate
Each banner uses 40/9 4 4/9 so 40/9 = 4/40 Making the whole number of 4 and 5. I hope I helped. It’s a little hard to explain.
Answer:
your answer is 7 because 9 times 2 = 18 then + 7 = 25
Step-by-step explanation:
Answer:
1/3.
Step-by-step explanation:
The 2 events are independent so we multiply the 2 probabilities.
Prob(rolling an odd number) = 3/6 = 1/2.
Prob(rolling a number greater than 2) = 4/6 = 2/3.
The required probability = 1/2 * 2/3
= 2/6
= 1/3.
During the ninth second, the object will fall at 272 feet.