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Tanzania [10]
4 years ago
5

A single die is rolled twice. Find the probability of rolling an oddnumber the first time and a number greater than 2 the second

time.
Mathematics
1 answer:
harkovskaia [24]4 years ago
5 0

Answer:

1/3.

Step-by-step explanation:

The 2 events are independent so we multiply the 2 probabilities.

Prob(rolling an odd number) = 3/6 = 1/2.

Prob(rolling a number greater than 2) = 4/6 = 2/3.

The required probability = 1/2 * 2/3

= 2/6

= 1/3.

You might be interested in
What two numbers are located 1/2 of a unit form 1/6 on the number line
weeeeeb [17]
Basically we need to add and subtract 1/2 from 1/6:

(1) 1/6 - 1/2 = 1/6 - 3/6
= -2/6
= -1/3

(2) 1/6 + 1/2 = 1/6 + 3/6
= 4/6
= 2/3

Therefor the two numbers that are located 1/2 unit from 1/6 are -1/3 and 2/3
5 0
3 years ago
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
9/10( -2/3) ( symplify )
levacccp [35]
-3/5 because you multiply 9/10 by -2/3
4 0
4 years ago
Jus help im in a timed assigment
gogolik [260]
0.59
x 0.37
413
1770
2183
4 0
3 years ago
Write the following function in standard form. Show your work. y=(x-5)(x+5)(2x-1)
Gnesinka [82]

Answer:

\boxed{y=4x^3-x^2-50x+25}


Step-by-step explanation:

The given function is


y=(x-5)(x+5)(2x-1)


Observe that, the first two factors are from difference of two squares.


\Rightarrow y=(x^2-5^2)(2x-1)


\Rightarrow y=(x^2-25)(2x-1)

We expand the brackets using the distributive property to obtain;

\Rightarrow y=2x^2(2x-1)-25(2x-1)


\Rightarrow y=4x^3-x^2-50x+25


The above function is now in standard form, since the terms are arranged in descending powers of x.



4 0
4 years ago
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