Answer:
See explaination
Explanation:
We already know that people all over the world are using the internet to communicate with each other to store their personal data, for the entrainment working in internet, doing online shopping and a lot of things. The user can faced with many threats. These threats are of different form.
The listed and explained below are some of the threats;
a) Compromised browser:-
Most popular browser are targeted and any security flaws exploited immediately. Criminals uses the flaws to gain access to sensitive document and shadow users browsing activity.
Phishing:-
Phishing is simply referring to the spam email or websites. Most times it is used to steal ones data, identity and funds. It looks genuine, this is what makes it hard to detect .
Poisoned websites:-
These are the fake link with hidden malware where the malware creator create a juicy news /video link which attract the user but the destination affect the PCs and the PC give a big virus alert and then compelled a visitor to be aware of the malware.
Misused social media sites:- These are often used in work place these are misused to spread Trojans and malware User download file and put the corporate network at risk .
These threats are not meaningful to the internet of Things (IOT) but there are different things like if you have a CCTV camera and it is connected to internet so by the threads anyone can take control over the cameras it can shut down the camera delete the recording of the camera and other things. There are the other threats.
It’s used to define the color or sound of a tone .
Biosphere..
hope it helepd
Resource management, you can think of the necter and pollen as resources and you are managing other bees to collect those resources.
Answer:
Fragment 1: size (1332), offset value (0), flag (1)
Fragment 2: size (1332), offset value (164), flag (1)
Fragment 3: size (1332), offset value (328), flag (1)
Fragment 4: size (781), offset value (492), flag (1)
Explanation:
The maximum = 1333 B
the datagram contains a header of 20 bytes and a payload of 8 bits( that is 1 byte)
The data allowed = 1333 - 20 - 1 = 1312 B
The segment also has a header of 20 bytes
the data size = 4777 -20 = 4757 B
Therefore, the total datagram = 4757 / 1312 = 4
