Mark has $16 more than Becca. Represent how much money Mark has
1 answer:
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Answer:
Yes
Step-by-step explanation:
This equation is in slope-intercept form, . If graphed, it would be a line.
Hope this helps!
Answer:
C
Step-by-step explanation:
So, we started out with 2,400 black rhinos.
And we know that they are declining at a rate of 10% per year.
In other words, each subsequent year will only have <em>90%</em> of the previous year's rhinos.
Therefore, our function is:
We can do some elimination first.
First, the starting point or y-intercept <em>must </em>be 2400 since that's the number of rhinos we started out with.
Therefore, we can eliminate A and D.
From the remaining choices B or C, we can technically also eliminate B. This is because from our function, we know it's exponential decay, and exponential decay is <em>not</em> a straight line.
However, to double check, let's check the population after 10 years using our function. So:
Use a calculator:
So, after 10 years, the population should be around 840.
B is definitely <em>not</em> 840 (at x=10). However, C is right around it.
Therefore, we can conclude that C is the right answer.
And we're done!
Answer:
N(1)=50 is a minimum
N(15)=4391.7 is a maximum
Step-by-step explanation:
<u>Extrema values of functions </u>
If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.
We are given a function (corrected)
(a)
First, we take its derivative
Solve N'(t)=0
Simplifying
Solving for t
Only t=1 belongs to the valid interval
Taking the second derivative
Which is always positive, so t=1 is a minimum
(b)
N(1)=50 is a minimum
(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15
(d)
N(15)=4391.7 is a maximum