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Blababa [14]
3 years ago
6

6th grade math 3m + 4m + 5 + 1 -7m

Mathematics
2 answers:
Andru [333]3 years ago
7 0
6 because 3+4=7 then 7+5=12 then 12+1 =13 and 13-7=6
elena55 [62]3 years ago
4 0

Answer:

6

Step-by-step explanation:

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Roger is training for the upcoming track season and records the number of miles that he runs each day for 20 days: 2.5, 0.5, 3.5
Leni [432]

Answer:

a

Step-by-step explanation:

I got right on edge

7 0
3 years ago
−0.178571428571429 as a faction
sergiy2304 [10]

-\dfrac{178571428571429}{1000000000000000}

6 0
4 years ago
Read 2 more answers
A cylinder has volume 45 pie and radius 3. What is its height?
liraira [26]

Answer:

5 units

Step-by-step explanation:

The <u>volume of the cylinder</u> is the area of the circle multiplied by it's height. Therefore, the volume of the cylinder is πr² × h, which when simplified, gives us πr²h. Let's substitute the volume and the radius in the formula to find the height.

⇒ πr²h = Volume of cylinder

⇒ (π)(3²)(h) = 45π

Now, simplify the equation to evaluate the area of the cylinder.

⇒ (π)(3²)(h)/(3²)(π) = 45π/(3²)(π)

⇒ (h) = 45π/(9)(π) = 45/(9) = 5 units

7 0
3 years ago
Write the first five terms of the sequence.<br><br> a_(n) = -1(1)/(3)^(n-1)
Annette [7]
That's a little messy :)

If that is: -1/[3^(n-1)]

-1, -1/3, -1/9, -1/27, -1/81


4 0
3 years ago
Squad root of 130 by using the Babylonian method. Let 11.5 be initial.
tangare [24]


The Babylonian method for approximating square roots is the recursive method given by:

Given:

x0≈k−−√
x
0
≈
k


Then:

xn+1=x2n+k2xn
x
n
+
1
=
x
n
2
+
k
2
x
n


where k
k
is the number for which we are approximating the square root.

So, armed with this formula, let's now answer the given questions:

1.) Fill in the missing info in the problem to find square root 130 by using the Babylonian method. Let 11.5 be your initial guess.

We will use 15 digits of precision here since it is not stated how many iterations to carry out:

x0=11.5
x
0
=
11.5


x1≈11.4021739130435
x
1
≈
11.4021739130435


x2≈11.4017542587143
x
2
≈
11.4017542587143


x3≈11.4017542509914
x
3
≈
11.4017542509914


x4≈11.4017542509914
x
4
≈
11.4017542509914


Thus, with 15 digits of accuracy, we may state:

130−−−√≈11.4017542509914
130
≈
11.4017542509914


2.) Use the Babylonian method for your next estimate of square root 115 by using 10.7262 as your guess what's your next result?

The next result here is approximately:

x1=10.72622+1152⋅10.7262≈10.7238055620816
x
1
=
10.7262
2
+
115
2
⋅
10.7262
≈
10.7238055620816



3.) Nails wants to use the Babylonia method to estimate square root 58 to the nearest hundredth her initial estimate is 7.8. What is her estimate after she correctly completes the Babylonian method once?

The next result here is:

x1=7.82+582⋅7.8=7.6179487¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
x
1
=
7.8
2
+
58
2
⋅
7.8
=
7.6
179487
¯


4.) If you use the Babylonian method to estimate square root 75 to the nearest hundredth, starting with the estimate 8. What is the next estimate?

The next result here is:

x1=82+752⋅8=8.6875
x
1
=
8
2
+
75
2
⋅
8
=
8.6875
6 0
3 years ago
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