The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
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Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about area here:
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To find missing lengths of sides
hope this helped have a nice day
Answer:
y = 2(x+3)(x-3)
Step-by-step explanation:
y = a (x-x1) * (x-x2) * (x-x3) * ... (x-xn)
x 1 to n represents the roots
Answer:
LCD = 36
Step-by-step explanation:
I'm sure it 36!!!!!!!!!!!!!
Answer:
2persent
Step-by-step explanation:
because there are 10 10 in 100