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mote1985 [20]
3 years ago
11

Simplify the following rational expression.

Mathematics
1 answer:
Nitella [24]3 years ago
5 0
I think it’s 22 don’t hate me if you get it wrong
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n the diagram, ABC and DBE are similar. What is the scale factor of the dilation that will map the preimage ΔABC onto the image
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7 0
3 years ago
7. Using the distance formula, calculate how far Hector threw the ball. (4 points: 2
iragen [17]

The required distance covered is 90 units

<h3>Distance formula</h3>

The formula for calculating the distance between two points is expressed as shown:

  • D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The required coordinates missing are (0, 42.78) and (90.42.78). Substiute the coordinate into the formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

D=\sqrt{(42.78-42.78)^2+(90-0)^2}\\D=\sqrt{(0^2+(90)^2}\\D = 90 units

Hence the required distance covered is 90 units

Learn more on distance formula here: brainly.com/question/1872885

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2 years ago
If the dimensions of a rectangle are enlarged by a
AfilCa [17]

Answer:

area of a rectangle = 4(length × width)

6 0
3 years ago
What is the value of x?<br><br> 3<br> 4<br> 6<br> 8
bekas [8.4K]
The longer sides of the rectangles should be the same value, so we can make the lower part of the equation equal to 18, which is 4.
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8 0
3 years ago
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This hyperbola is centered at theorigin. Find its equation.Foci: (-2,0) and (2,0)Vertices: (-1,0) and (1,0)
beks73 [17]

SOLUTION

From the question, the center of the hyperbola is

\begin{gathered} (h,k),\text{ which is } \\ (0,0) \end{gathered}

a is the distance between the center to vertex, which is -1 or 1, and

c is the distance between the center to foci, which is -2 or 2.

b is given as

\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}

But equation of a hyperbola is given as

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

Substituting the values of a, b, h and k, we have

\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}

Hence the answer is

\frac{x^2}{1}-\frac{y^2}{3}=1

5 0
11 months ago
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