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MArishka [77]
4 years ago
5

HELP!!! PLEASE! ALGEBRA 1 RELATED! Look! Don't write answer till i added pic!

Mathematics
1 answer:
g100num [7]4 years ago
7 0

Answer: it is the first step

Step-by-step explanation: Because on the first step it has an exponent and you aren’t suppose to add them

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crimeas [40]

Answer:

c=18

Step-by-step explanation:

54 divided by 9 is 6

6 times 3 is 18

3 0
4 years ago
[Calculus] particle at rest question. Show steps, please!
Vinvika [58]

Answer:

E

Step-by-step explanation:

We are given that a particle's position along the x-axis at time <em>t </em>is modeled by:

x(t)=2t^3-21t^2+72t-53

And we want to determine at which time(s) <em>t</em> is the particle at rest.

If the particle is at rest, this suggests that its velocity at that time is 0.

Since are we given the position function, we can differentiate it to find the velocity function.

So, by differentiating both sides with respect to <em>t</em>, we acquire:

\displaystyle x^\prime(t)=v(t)=\frac{d}{dt}\big[2t^3-21t^2+72t-53\big]

Differentiate. So, our velocity function is:

v(t)=6t^2-42t+72

So, we will set the velocity to 0 and solve for <em>t</em>. Hence:

0=6t^2-42t+72

We can divide both sides by 6:

0=t^2-7t+12

Factoring yields:

(t-3)(t-4)=0

By the Zero Product Property:

t-3\text{ and } t-4=0

Hence:

t=3\text{ and } t=4

Therefore, at the 3rd and 4th seconds, the velocity of the particle is 0, impling that the particle is at rest.

Our answer is E.

6 0
3 years ago
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Elis [28]

Answer:

false for 0.7 it would have to be 7/10

Step-by-step explanation:

7 0
3 years ago
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cupoosta [38]
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5 0
4 years ago
Please help I’ll give brainliest
Murrr4er [49]

Answer:

The answer for this question is 3

6 0
3 years ago
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